how would you solve
(10x^3y^5)^-3
I dont really understand this please help
2007-11-21 17:10:42 · 5 answers · asked by ? 2 in Science & Mathematics ➔ Mathematics
(10x^3y^5)^-3
= 1 / (10x^3y^5)^3
= 1/(1000x^9 y^15)
2007-11-21 17:15:53 · answer #1 · answered by MsMath 7 · 0⤊ 0⤋
(10x^3y^5)^-3
= 1 / (10x^3y^5)^3
= 1/(1000x^9 y^15)
2007-11-22 05:09:32 · answer #2 · answered by catsfanj 3 · 0⤊ 0⤋
First: (raise each term by 3 ) when you combine exponents with one variable - always multiply exponents.
(10^3)x^3(-3) y^5(-3)
1000x^(-9)y^(-15)
*Rule - variables can't have negative exponents - place the term(s) over 1 - to make exponents positive.
[1000x^(-9)y^(-15)]/1
Sec: place the variables (with negative exponents) in the opposite position - the denominator.
1/[1000x^9y^15]
2007-11-22 01:23:58 · answer #3 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
[11]
(10x^3 y^5)^-3
=1/(10x^3 y^5)^3
=1/1000 x^[3*3]y^[5*3]
=1/1000 x^9 y^15
2007-11-22 01:16:55 · answer #4 · answered by alpha 7 · 0⤊ 0⤋
"Solve" suggests that there should be an equation which , in turn, requires = sign.
Should say, in this example, "simplify" the expression:-
Answer
1 / [ (1000)(x^9)(y^15) ]
2007-11-22 05:21:47 · answer #5 · answered by Como 7 · 0⤊ 0⤋