Can anyone answer this for me, please?

Question

Consider the following system at equilibrium: A(aq) B(aq) <--->2C(aq)
Classify each of the following actions by whether it causes a leftward shift, a rightward shift, or no shift in the direction of the net reaction.
Increase [A], Increase [B], Increase [C], Decrease [A], Decrease [B], Decrease [C], Double [A] and halve [B], Double both [B] and [C].

Answer 1

The principle is that the reagents shift conc to reduce the effect of the change. In terms of the math: [C]^2/[A][B] = K
1. Increase A leads to more C being formed
2. Increase B leads to the same
3. Increase C leads to more A and B being formed.
4. Decrease A leads to a decrease in C
5. Same deal

Answer 2

Leftward Shift:
Decrease [A]
Decrease [B]
Increase [C]
Double both [B] and [C]

Rightward shift:
Increase [A]
Increase [B]
Decrease [C]

No Shift:
Double [A] and halve [B]

Answer 3

Increase A causes righward shift

Increase B causes rightward shift

Increase C causes leftward shift

Decrease A and Decrease B cause leftward shift

Decrease C causes a rightward shift

Double A is the same as increasing A which causes a rightward shift, Halving B is the same as decreasing B - leftward shift

Double B and C leaves the equilibrium the same

Answer 4

This is an illustration of Le Chatelier's Principle.

Increase [A], shifts right.
Increase [B], shifts right.
Increase [C], shifts left.
Decrease [A], shifts left.
Decrease [B], shifts left.
Decrease [C], shifts right.

For the last two, look at the equilibrium expression for this reaction:
K = [C]² / [A][B]
Assume K is 1, and initially all concentrations are 1. Plug in the numbers appropriately.

If K < [C]² / [A][B], the equilibrium shifts left. If K > [C]² / [A][B], it shifts right.

Answer 5

rebecca's best.

Answer 6

i suggest you read abt Le Chatelier's principle so you can answer other questions like this.