1. Evaluate -|-340|.
-|-340|= -340 absolute will give you positive and the negative sign will u the negative again.
Answer: -340
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2. Evaluate |-14|.
|-14| = 14 the absolute will always give you the positive part of the value. Except 0, zero
Answer: 14
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3. Determine the maximum and minimum values of the following set of numbers:-12,24,13,7,-24,5,0
You need to arrange the distribution into ascend order,
-24, -12, 0, 5, 7 12, 24
The minimum will be -24 or the smallest on your distribution, Maximum will be 24 which is the largest on your distribution.
Using ti-83 plus calculator, you need to plug the numbers into STAT, then EDIT, enter all the numbers without order is okay, then enter STAT, SORTA(, then plug in 2ND 1 for L1, 2 for L2 and etc... then hit enter, it will say DONE, Then go back to STAT, EDIT, you will see all the numbers in order.
Answer: Min: -24, Max: 24
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4. Determine the maximum and minimum values of the following set of numbers.2, -8, 1/2, -5, 3, 9/4, -7, -73/9
Do as I suggest above, you will get the data as,
-73/9, -8, -7,-5,.2, .5, 3
You have min: -73/9, Max 3
Answer: Min: -73/9, Max 3
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5. Place the following set of numbers in ascending order: 22,-15,9,-4,11,-1,17
Do as I suggest and you will get,
-15, -4, -1, 9, 11, 17, 22
Answer:-15, -4, -1, 9, 11, 17, 22
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6. Place the following set of numbers in ascending order.-2/3, 1/6,7/8, -5/9, 3/4
Do as I suggest and you will get,
-2/3, -5/9, 1/6, 3/4, 7/8
Answer:-2/3, -5/9, 1/6, 3/4, 7/8
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7. Place the following set of numbers in ascending order.
-2, 8, 0, 2, -3, -20, 11
Do as I suggest and you will get,
-20, -3, -2, 0, 2, 8, 11
Answer:-20, -3, -2, 0, 2, 8, 11
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8.Which of the following numbers are integers? 3,2/3, -3,101.1,-5/7
Integers mean whole, entire, including positive and negative, therefore,
3, -3
Answer: -3, 3
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9.Find the first and third quartiles, Q1 and Q3, of the following set of numbers:
To calculate the quartiles, arrange the observations in increasing order and locate the median M in the ordered list of observations
The first quartile Q1 is the median of the of the observations whose position in the ordered list is to the left of the location of the overall median.
The third quartile Q3 is the median of the observations whose position in the ordered list is to the right of the location of the overall median.
Answer: you didnt provide data so I put definition.
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10, Find the first and third quartiles, Q1 and Q 3 of the following:7, 15, 13, 13, 12, 9, 11, 19,
Put in ordered list, you get,
7, 9, 11, 12, 13, 13, 15, 19 and you have 8 observations,
you need to know the overall median, M, its the mean of the 4th and 5th number, which is 12+13 = 25
25/2 = 12.5 = M = overall median,
Min = 7, M = 12.5, Max = 19
7, 9, 11, 12, 13, 13, 15, 19
for Q1, you have 7, 9, 11, 12. Q1 will be mean of 2nd and 3rd number which is 9 + 11 = 20
20/2 = 10
Q1 = 10
for Q3, you have 13, 13, 15, 19 and Q3 will be mean of 2rd and 3rd number which is 13+15 = 28
28/2 = 14
Q1=10,
Q3=14
Answer: Q1= 10, Q3 = 14
*still confused? write back
2007-11-21 14:06:57
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answer #1
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answered by john_lu66 4
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-10
1) -340
2) 14
3) min=-24. max=24
4) min=-73/9, max=5
5) -15,-4,-1,9,11,15,17,22
6) -2/3,-5/9,1/6,3/4,7/8
7) -20,-3,-2,0,2,8,11
#8,9,&10 are all on how you are doing this in class.
#8example:
Positive integers are all the whole numbers greater than zero: 1, 2, 3, 4, 5, ... . Negative integers are all the opposites of these whole numbers: -1, -2, -3, -4, -5, … . We do not consider zero to be a positive or negative number. For each positive integer, there is a negative integer, and these integers are called opposites. For example, -3 is the opposite of 3, -21 is the opposite of 21, and 8 is the opposite of -8. If an integer is greater than zero, we say that its sign is positive. If an integer is less than zero, we say that its sign is negative. so if you just want the integer, then it is all of them, or if you want the real set, this is 3,-3
#9 and 10 are done diff by diff people. some take the average and others don't. Given the set {1, 3, 5, 8, 9, 12, 24, 25, 28, 30, 41, 50} we would find the first and third quartiles as follows:
There are 12 elements in the set, so 12/4 gives us three elements in each quarter of the set.
So the first or lowest quartile is: 5, the second quartile is the median 12, and the third or upper quartile is 28.
However some people when faced with a set with an even number of elements (values) still want the true median (or middle value), with an equal number of data values on each side of the median (rather than 12 which has 5 values less than and 6 values greater than. This value is then the average of 12 and 24 resulting in 18 as the true median (which is closer to the mean of 19 2/3. The same process is then applied to the lower and upper quartiles, giving 6.5, 18, and 29. This is only an issue if the data contains an even number of elements with an even number of equally divided sections, or an odd number of elements with an odd number of equally divided sections.
i quit, do your own homework
Ps. dude's answers above mine are not correct.
2007-11-21 21:50:07
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answer #2
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answered by info2know 3
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