Also simplify m^3 over 7 divided by m^7 over 28
2007-11-21 13:30:20 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x-7 /15 = 3/5
5x - 35 = 45
x = 9-7 = 2
ANS: x= 2
m^3 / 7 ÷ m^7/ 28
m^3 / 7 * 28/m^7
28m^3 / 7m^7
4/m^4
ANS: 4/m^4 ... 4 over m^4
2007-11-21 13:34:59 · answer #1 · answered by David F 5 · 0⤊ 4⤋
x-7/15=3/5
= x-7/15= 9/15
= x/15= 16/15
=x=15
2007-11-21 21:11:13 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Do you mean (x-7)/15 = 3/5 or x - (7/15) = 3/5? I'll solve both.
1. (x-7)/15 = 3/5
First: eliminate fractions - multiply the least common denominator (15 - multiple of 5 & 15) with each term.
15[(x-7)/15] = 15(3/5)
Sec: cross cancel the same terms - combine the rest.
x-7 = 45/5
x - 7= 9
Third: isolate "x" - add 7 to both sides (when you move a term to the opposite side, always use the opposite sign).
x - 7+7= 9+7
x = 16
2. x - (7/15) = 3/5
First: eliminate fractions - multiply the least common denominator (15) with each term.
15(x) - 15(7/15) = 15(3/5)
Sec: cross cancel the same terms - combine the rest.
15(x) - 7 = 15(3/5)
15x - 7 = 45/5
15x - 7 = 9 (add 7 to both sides).
15x - 7+7 = 9+7
15x = 9+7
15x = 16 (divide both sides by 15).
15x/15 = 16/15
x = 16/15
2007-11-21 16:10:59 · answer #3 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
(x-7)/15 = 3/5
multiply both sides by 15
x - 7 = 9
Solve for x, add 7 to both sides
x = 16
(m^3/7)/(m^7)(28)
Invert denominator and multiply
(m^3/7)(28/m^7)
(28m^3)/(7m^7)
Reduce the fraction by reducing the coefficients (divide both by 7) then reduce the x terms (subtracting the exponets in equal amounts m^3 will drop out completely).
4/m^4
2007-11-21 13:35:30 · answer #4 · answered by Brian K² 6 · 1⤊ 1⤋
(x-7)/ 15 = 3/5
cross multiply:
5(x-7) = 45
5x - 35 = 45
5x = 80
x= 16
(m^3/7) / (m^7/28)
division is the same as reciprocal multiplication
= (m^3/7) * (28/m^7)
= 4/m^4
2007-11-21 13:35:17 · answer #5 · answered by sayamiam 6 · 1⤊ 1⤋
Distribute each and every type into each and every binomial: 7 + 12 - 2x = 15 + 15 - 3x combine like words: 19 - 2x = 30 - 3x upload the two factors by way of 3x: 19 - 2x + 3x = 30 - 3x + 3x 19 + x = 30 ultimately, subtract the two factors by way of 19: 19 - 19 + x = 30 - 19 So x = 11 i'm hoping this enables!
2016-12-10 03:09:57 · answer #6 · answered by giallombardo 4 · 0⤊ 0⤋
(x - 7)/15 = 3/5
(x - 7)/3 = 3
x - 7 = 9
x = 16
Answer: x = 16
Proof:
(16 - 7)/15 = 3/5
9/15 = 3/5
3/5 = 3/5
2007-11-21 13:40:28 · answer #7 · answered by Jun Agruda 7 · 3⤊ 1⤋
x-7 over 15= 3 over 5?
cross mult,
(x-7)/15 = 3/5
(x-7)*5 = 3*15
5x - 35 = 45
5x = 80
x = 80/5 =16
Answer: x = 16
*still confused? write back
2007-11-21 13:35:06 · answer #8 · answered by john_lu66 4 · 1⤊ 2⤋
x=16
2007-11-21 13:35:26 · answer #9 · answered by info2know 3 · 0⤊ 3⤋
multiply both sides by15
x-7=9
x=16
2007-11-21 13:35:35 · answer #10 · answered by someone else 7 · 1⤊ 2⤋