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Using Zaitsev's rule...

A. (E)-hex-2-ene
B. hex-1-ene
C. (Z)-hex-2-ene
D. They are all equal


I understand Zaitsev's rule, where more substituted double bonds are usually more stable, i just don't understand the nomenclature of the compounds. I've never heard of hex-1-ene before or anything like that.

Thank you.

2007-11-21 13:25:04 · 2 answers · asked by Paulllll C 3 in Science & Mathematics Chemistry

2 answers

I believe it would be A. (E)-hex-e-ene since it the most substituted alkene from the list. Also, because it is an E isomer- the two large groups are on different sides of the molecule, there is less steric interaction, making it more stable.
hope that answered your question

2007-11-21 13:36:33 · answer #1 · answered by butterfly 1 · 1 0

About the stability I can't help, but the nomenclature I recognize.

hex-1-ene means the double bond is in the first position:
C=C-C-C-C-C

hex-2-ene means the double bond is in the second position:
C-C=C-C-C-C

(z) is equivalent to cis, and (e) to trans.

2007-11-21 21:43:11 · answer #2 · answered by Roger the Mole 7 · 1 0

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