Give an ordered pair that is the solution to the equation y = 5x + 2.?

Question

Please show your work....I think this is really hard and need help understanding...

Answer 1

If x = 1:
y = 5(1) + 2
y = 7
So one pair is (1,7)

Answer 2

If the ordered pair might desire to be *the* answer, no longer basically any pair that satisfies the equation, then it might desire to by some means incorporate the equation itself. One answer is (x, 5x + 2). For this answer, the y in the accepted pair (x, y) grew to become into replaced with the final hand area of the equation. different solutions are available, yet are unnecessarily complicated. as an example, if we resolve the equation for x, we locate that x = (y - 2) / 5. for this reason, yet another answer is ((y - 2) / 5, y). A greater formal physique of techniques to the priority could be to apply set builder notation. In set builder notation, you will possibly desire to write something like: {(x, 5x + 2) | x is a actual extensive form}. it is study as "the set of all ordered pairs (x, 5x + 2), such that x is a actual extensive form." however the fewer complicated answer, (x, 5x + 2), is in all probability the wished answer because of the fact it represents a ordered pair in accordance with a variable, x, particularly than a sequence of ordered pairs.

Answer 3

Just pick a number for x, put it into the equation to get y, and theres your ordered pair

(0, 2)
(1, 7)
(2, 12)

etc...

Answer 4

so any of the ordered pairs that have been given above.

Pick 2, plot them on a graph. Draw a line connecting the 2
points - it can extend left and right of those points too.

All the rest of the solutions to this problem are on that line.

Answer 5

2 is where the line crosses the 'y' (up and down) line. from there, go 5 up and one right.
So the first point could be 0,2. From there, go up 5 and right one. That would be 1, 7

look at the format
mx+b=y
m is the slope (rise over run, so in this case 5/1) and b is where it hits y

Answer 6

Put in any value for x:

x = 0 (y intercept)
y = 5*0 + 2
y = 2

(0,2) is one solution

x = 1
y = 5*1 + 2
y = 7

(1,7) is another solution

Best of luck!

Answer 7

It's easiest to just "plug in", or substitute, numerical values in for x into the equation and see what value for y "pops out".

Let x = 0
y = 5(0)+2
y = 2

Ordered pair: (0,2)

Or another one...
Let x = 1
y = 5(1)+2
y = 7

Ordered pair: (1,7)

Hope this helps!

Answer 8

y = 5x + 2


x = {0, 1, 2, ...} gives from the given equation
y = {2, 7, 12, ...}

Ordered pairs are (0, 2), (1, 7), (2, 12), ...

Answer 9

In Mathematics simultaneous equations are a set of equations containing multiple variables. This set is often referred to as a system of equations.

Question does not make sense, unless we have an additional equation, to find out a unique solution.

Answer 10

any order pair?

when x = 0, y = 2 so (0,2)