Geometry Problems?

Question

1. Write the equation 4x-y=3 in slope-intercept form.

A. y = -4x-3

B. y = -4x+3

C. y = 4x-3

D. y = 4x+3


2. The graph of x=3 can be described as

A. a vertical line through the point (3,0)

B. a vertical line through the point (0,3)

C. a horizontal line through the point (3,0)

D. a horizontal line through the point (0,3)

Answer 1

4x-y=3 to get slope intercept for you need to get y by itself so add y to both sides you get
4x=y+3 then subtract 3 from both sides
4x-3=y that is your slope intercept form

x=3 graph would mean that for whatever number y is x will always be 3. so graph points with any y like (3,0) (3,1) (3,-1) and you will see that the line is a vertical line going through the point (3,0)

Answer 2

You need to know slope-intercept form: y = mx + b

Notice when x=0, y = b so b is the y-intercept. For a change of 1 unit in x, y changes by m(1) = m so m is the slope. So any time you solve for y you have put the linear equation in slope-intercept form . Solving your equation in (1) gives
y = 4x + (-3) so slope is 4 and y-intercept is -3.

In problem (2) x=3 for any value of y so the points ((3,0), (3,1), (3,2), etc. These points all lie on the vertical line through x=3.

Answer 3

1. Write the equation 4x-y=3 in slope-intercept form
y = 4x -3

answer is C
2. The graph of x=3 can be described as

Answer is A. a vertical line through the point (3,0)

Answer 4

1. y=mx+b
the answer would be= C
2. The answer is A

Answer 5

1. D
2. A (X is vertical)

Answer 6

1. C
2. A

Answer 7

1 C
2 A

This isn't really geometry its algebra...