Chem Help?

Question

The internal energy change is 4:11 kJ when
an ideal gas expands from 3.50 to 28 liters
at a constant external pressure of 2:95 atm.
What is the heat absorbed by the gas from its
surroundings? Answer in units of kJ.

Answer 1

It seems to me that you have difficulty to convert energy in atm*L unit to Joules. Let me tell you an easy way to remember.
As you know, that the gas constant can be written in different way such as:
R = 0.08206 atm*L/T*mol = 8.314 joule/T*mol
That is to say: 0.08206 atm*L = 8.314 joule,
or: 1 atm*L = 101.3 joules.

The work done by the system on the environment is:
(28-3.50)*2.95*101.3 = 7.32 kJ
The heat absorbed by the gas from its surrounding is:
4.11kJ + 7.32kJ = 11.43 kJ.