Can someone help me find the tangential and normal components of this acceleration vector?

Question

r(t) = (1+t)i + (t^2 -2t)j

Answer 1

Hi,
Normally I wouldn't try this because it's been a long time since I did it and my memory of how to do it is rusty. But your problem has been here a long time, so I'll see if I can at least give you something to think about.
r(t) = (1+t)i + (t^2 -2t)j
r'(t) = i +(2t-2)j
r"(t) = 0i +2j
aT =(v•a)/||v||
=(I +(2t-2)j •2j)/√[1² +(2t-2)²]
=(4t-4)/√(4t²-8t+5)

aN =(vxa)/||v||
=2/√[1² +(2t-2)²]
=2/√(4t²-8t+5)

Hope this is of some help.

FE

Answer 2

Certainly. The quadrilateral dissection is assimilated through the vortex congruent with the integral of the square root of the tangent and covalent integers of X-15/45. Simple

Answer 3

Bob, be sure to pre-heat the oven to 350 degrees and make sure the turkey is totally thawed. Place the bird in the oven and bake for 5 to 6 hours, depending on the size. Smother the turkey in turkey gravy and enjoy........