If I have a balloon that holds 70 cubic meters of gas what will the approximate surface area be?

Question

Thank you very much everyone, I now have everything I need, I will be choosing first answer as best answer. Thank you

Answer 1

We have to assume this is a spherical balloon:

Formula for volume of a sphere:
V = 4/3 π r^3

Formula for surface area of a sphere:
S.A. = 4 π r²

Solve for the radius:
70 = 4/3 π r^3
r = cube root (70 * 3/4 / π)
r ≈ 2.55664136
r ≈ 2.56 m

Now solve for the surface area:
S.A. = 4 π (2.56)²
S.A. ≈ 82.14 sq. meters

Answer 2

Assuming the balloon is a sphere----
The volume of a shpere is 4/3 pi r^3
The area of the surface is 4 pi r^2
The volume of gas is 70 meters^3

solve for the radius
70 = 4/3 pi r^3
r=2.56 meters
So the surface area is
4*pi*2.56*2.56 meters squared
=82.4 square meters

Answer 3

Vol = 4/3 pi r^3 = 70

r = 2.554

Area = 4 pi r^2 = 81.984

Answer 4

if you consider a spheric balloon, then the volume will be given by
V=(4/3)*π*R³
(R is the radius)

Then you find the radius by
70=(4/3)*π*R³
as π equals 3,1415926...
you'll find R=2,56 meters

Then you find the area will be
A=4*π*R²
A=82,14 square meters