Find the volume of a triangular prism whose base is regular with sides that measure 12cm and whose height 10?

Question

Find the volume of a triangular prism whose base is regular with sides that measure 12cm and whose height is 10cm.

Answer 1

Volume of triangular prism = area of the base* height

area of the base is area of equilateral triangle of 12cm side

the h of equilateral triangle = sqrt(3)a/2

=>sqrt(3)* 12/2 = 6 sqrt(3)

area of base = bh/2 = 12*6sqrt(3)/2 = 36 sqrt(3)

volume = area * h = 36sqrt(3)* 10 = 360sqrt(3) sq.cm

Answer 2

The question or problem isn't well defined. Normally, to determine the volume of a triangular prism, you need three figures--the width of the base of the triangle, the altitude of the triangle, and the length of the rectangular sides. Then you multiply base times altitude, divide by 2, and multiply by length. When you say that the base (of the prism?) is "regular," do you mean that it's square--that the length of the rectangular sides is the same as the width of the base of the triangle? Or do you mean simply that the sides of the base of the prism are parallel? Or that the triangluar ends are equilateral? Or something else? If the base of the prism is square, then the area if the triangular end is 60 sq. cm., and the volume of the whole thing is 720 cubic. cm. However, be sure you have all the dimensions. Check what the problem says again and resubmit your quetion if you need to.

Answer 3

720 Cubic cm

Answer 4

I think you need this formula.

V =(1/3)Bh

V =(1/3)12 times 10

V = 40 cubic centimeters

Answer 5

720 cubic centimeters...