2w^2-3w-35 factor?

Answer 1

( 2w + 7 ) ( w - 5 )
Check
2 w ² - 10 w + 7 w - 35
2 w ² - 3 w - 35 (as required)

Answer 2

Divide all coefficients by 2 to get:
2(w^2 - 1.5w - 17.5)

On your Albert Nestler 23/R (Albert Einstein and Werner Von Braun's favorite slide rule), set the left index of the C scale over 1.75 on the D scale.

Move the cursor down the slide, comparing the values on the CI scale to the D scale. Eventually, you'll come to two values that are 1.5 apart.

In fact, that will happen when the 5 of the CI scale is above the 3.5 of the D scale.

That means (w^2 - 1.5 w - 17.5) = (w -5)(w + 3.5)

Your final factor answer is:

2(w + 3.5)(w - 5)

If you don't like having non-integers in one of the terms, multiply the 2 into the second term to get:

(2w + 7)(w-5)

Answer 3

Look at the first number - you know one parenthesis will have a 2x, the other x.
(2x )(x )
Find the factors of the third number - it is either 1&35 or 5&7. Since it is negative, the signs will be different. The rest is trial and error to determine which parenthesis each goes in - do the Outer and Inner.
(2x 5)(x 7)
14x - 5x = 9x
(2x 7)(x 5)
10x - 7x = 3x
The middle sign is negative so the number that gave you the 10x has the (-) sign.
(2x+7)(x-5)

Answer 4

2w + 7 )( w -5

Answer 5

(2w + 7) (w - 5)

Answer 6

(2w + 7)(w-5)

Answer 7

(2w+7)*(w-5)

Answer 8

(2w+7)(w-5)

Answer 9

(2w+7)(w-5)
2w*w=2w^2
7*w=7w
-5*2w=-10w
7*-5=-35

2w^2-3w-35

Answer 10

It has first of all w status on my own for the two aspects. the different side is an integer. The integers could upload as much as 3 and multiply as much as eight. I cant discover any blend which could try this. This equation is unsolvable.