I dont know what to do with this problem after multiplying 2.19 amperes by the time in seconds. Then afterwards dividing it by the constant 96485 coulombs and left with moles of electrons: how do i get the mass they are asking me for?
1) Gold can be deposited by electrolysis. What mass of gold in g will be deposited by the electroplating of Au(NO3)3 using 2.19 amperes for 3.03 hr?
2007-11-21 01:39:49 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
why will I divide by 3 when the valence of gold is 1?
2007-11-21 02:29:57 · update #1
Since you have gotten to moles of electrons, you need to recognize that each mole of gold deposited will require 3 moles of electrons (since you're going from Au3+ ions to Au(s)). So, dividing moles of electrons by 3 gives you moles of gold. Then using the atomic weight of gold, you can calculate the mass deposited.
2007-11-21 01:47:01 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋