With Kobe looking like he is here to stay..for now.
Bynum is looking impressive. Farmar is ridiculously good. Lakers are a deep deep team. I say they will take it to the finals. Huge upset. LA drama all the way.
2007-11-20 22:47:31 · 11 answers · asked by Rachmanioff 1 in Sports ➔ Basketball
They are deep in mid-level talent. With SA, DAL, PHX, UTA, etc., a first round exit is guaranteed.
2007-11-20 23:24:43 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Bynum, Farmar and Kobe are looking pretty good and I think that will help them get to the playoffs so i think it'll be like most... Just loosing to Phoenix in the first round LIKE USUALL
2007-11-21 06:23:10 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Depends who's at the number 6th 7th and 8th spot! I don't think the Lakers are good enough to top the 5th spot! Theirs:
The Texas Triangle Rockets, Mavs, Spurs
Suns, Denver, and even the Hornets, but they started the injury-prone-year!!!
2007-11-21 08:44:42 · answer #3 · answered by Amo la pallacanestro 5 · 0⤊ 0⤋
Could be 2nd round or Conference finals.
They beat the Suns, the Rockets, the Jazz and the Pistons.
So long as they manage to get over San Antonio and Dallas.
They are amazing this year!
2007-11-21 00:28:44 · answer #4 · answered by Einsteinman 2 · 1⤊ 1⤋
The Suns will sweep them in the 1st round. It is becoming a Kobe tradition.
2007-11-21 03:37:29 · answer #5 · answered by xblee1 5 · 0⤊ 1⤋
Nope, the Lakers are not good enough, especially with a sulking superstar who is too individualistic. They will probably just get into the playoff.
2007-11-20 23:02:00 · answer #6 · answered by alanto72 2 · 0⤊ 1⤋
they will be out in 4 games, round 1
2007-11-21 00:37:45 · answer #7 · answered by Anonymous · 1⤊ 1⤋
They'll be an 8 seed, and go down in the first round.
2007-11-20 23:04:09 · answer #8 · answered by Anonymous · 1⤊ 1⤋
Lakers 08 champs all the way !
2007-11-21 04:33:48 · answer #9 · answered by ???? 5 · 1⤊ 2⤋
They'll go deep into the loser pile.. Like always
2007-11-21 23:44:01 · answer #10 · answered by Flying Fish Nugget 3 · 0⤊ 0⤋