No idea sorry, thanks for the point.
2007-11-20 22:12:45
·
answer #1
·
answered by Rissa 7
·
0⤊
0⤋
If you are going to accept online payments or buy anything online you are realistically going to need your own credit or debit card.
Paypal when you sign up will let you also sign up one of their basic cards so you can use their services. (assuming you have verifiable information)
check out http://paypal.com
I've used paypal for years both for online sales and processing the occasional on-site client credit card when I was doing on-site computer consulting. For the on-site clients I built a simple web page so the client could make the payment: http://troach.net/quickpay.htm if anyone is curious.
If your concern is security most groups have very secure processing and as long as you are careful about not giving out your passwords or other key information it is reasonably safe.
hope this helps.
2007-11-20 23:09:03
·
answer #2
·
answered by jerrys1960 5
·
0⤊
0⤋
I think it is impossible, not in places where the credit is very important and the only card to have is the credit card........I guess, they are still on the way thinking on how they can od such business...meanwhile , why not start your own..who knows??
2007-11-20 22:15:53
·
answer #3
·
answered by E@rthGoddess 6
·
0⤊
0⤋
you really cant do that, just get a debit card, its free, just put 5 dollars into a checking account
2007-11-20 22:12:19
·
answer #4
·
answered by CrunchyNugz 2
·
0⤊
0⤋
without credit card? then how people are gonna pay ya?
2007-11-20 22:38:25
·
answer #5
·
answered by ItzJonn 4
·
0⤊
0⤋
i doubt you can do it without the cards.
2007-11-20 22:12:28
·
answer #6
·
answered by icezkori 3
·
0⤊
0⤋
the site where ppl are naive.
2007-11-20 22:18:55
·
answer #7
·
answered by ♥Charmed One♥ 7
·
0⤊
0⤋
no where nobody is that trusting
2007-11-20 22:15:55
·
answer #8
·
answered by Mrs. Helena Lomax 5
·
0⤊
0⤋
Yahoo Q & A :-)
2007-11-20 22:12:24
·
answer #9
·
answered by pandurang j 3
·
0⤊
1⤋
Don't think have.
2007-11-20 22:12:05
·
answer #10
·
answered by Peter C 1
·
0⤊
0⤋