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A bank messanger's bag contains $10,800 made up of one, five, ten, and twenty dollar bills. There are an equal number of each of these bills. How many twenty dollar bills is the messanger carrying in the bag?

I need help!! Badly!! I have been working on this problem for two hours and i can't seem to get it. Please and thank you!!!!!

2007-11-20 16:54:35 · 9 answers · asked by Jeff M 1 in Education & Reference Homework Help

9 answers

since there are the same number of bills....

x + 5x + 10x + 20x = 10800
36x = 10800
x = 300

There are 300 pieces for each denomination.. So there are 300 twenty dollar bills.

2007-11-20 17:00:25 · answer #1 · answered by auztik 2 · 0 0

If there is an equal number of $1, $5, $10 and $20 bills, pretend that you spread them all out into piles of one of each bill in a pile. Each pile would then have $36 in it (one 1, 5, 10, and 20 dollar bill). There would be 10,800 divided by 36 piles or 300 piles. Each pile has a $20 bill so there must be 300 $20 bills

2007-11-21 00:59:51 · answer #2 · answered by SJM60 5 · 0 0

Answer is 300.

manager is carrying equal number of bills for 1, 5, 10 & 20.

suppose no of each bills is x.

then
1x + 5 x + 10x + 20x = 10800
36x = 10800
x = 10800 / 36
x = 300

so number of 20$ bills will be 300.

2007-11-21 01:14:10 · answer #3 · answered by rahul s 1 · 0 0

Use x as the number of bills of each type.
Therefore, for the value of the money, you have:
$1 bills = 1x = x
$5 bills = 5x
$10 bills = 10x
$20 bills = 20x
And all of this has to add up to $10,800; that is:
x + 5x + 10x + 20x = 10800
36x = 10800
x = 300
And remember, x is the number of bills of each type. So the number of $20 bills is simply x, or 300.

2007-11-21 01:01:30 · answer #4 · answered by niki 2 · 0 0

I want to go to Jenna's bank. I withdraw $10,800 and you are going to give me 2700 ea 20's , 10's , 5's, and 1's? Just the 20's only = 10,800. You would have given me an extra $43,200. Thank You very much. Stick to helping people with English problem's darling and spend more time working on your own math homework

2007-11-21 01:34:16 · answer #5 · answered by Mrcody 2 · 0 0

1x + 5x + 10x + 20x = 10800

if there are the same amount of each kind of bill you can use one variable to represent how many bills there are.

add the like terms

36x = 10800

divide both sides by 36

x = 300

there are 300 20s, 300 10s, 300 5s, and 300 ones.

hope this helps!

2007-11-21 01:00:11 · answer #6 · answered by Smiley 2 · 0 0

Hi Jeff. Let X equal the number of each type of bills.

We can write an equation using X:

(X)(1) + (X)(5) + (X)(10) + (X)(20) = 10800

Now, we have to solve for X.

Adding up the left side yields:

36X = 10800

Dividing both sides by 36 gives X = 300

We can test our answer to see if we got it right. $300 + $1500 + $3000 + $6000 = ?

10800! We got it right!

Hope this helps. Best wishes.

2007-11-21 01:02:26 · answer #7 · answered by Doctor J 7 · 0 0

Simple. divide 10800 by 4. The answer is 2700, which means in the bag there are 2700 $1 bills, 2700 $5 bills, 2700 $10 bills and 2700 $20 bills

2007-11-21 01:07:09 · answer #8 · answered by Anonymous · 0 1

wut is this... math you speak of.

2007-11-21 01:02:33 · answer #9 · answered by hytydd 1 · 0 1

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