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Ahh! I'm working on HW for my physics class on masting physics and I only have one more try on this problem:

An earth satellite moves in a circular orbit with an orbital speed of 6100 m/s. Find the time of one revolution. Find the radical acceleration.

Can someone help? This is all the data I was given

2007-11-20 16:42:57 · 3 answers · asked by Anonymous in Science & Mathematics Physics

3 answers

For circular motion, a = v^2 / r

v is the velocity of the satellite
r is the distance from the center of the Earth to the satellite

In this case, the radial acceleration is due to gravity from the Earth

a = G Me / r^2

where G is the Newton gravity constant, Me the mass of the Earth, and r the distance between the center of the Earth and the satellite.

Now put them together and solve for r:

G Me / r^2 = v^2 / r
G Me / r = v^2
G Me / v^2 = r

Now that you have r, you can use the first equation to get the acceleration a.

For the time for one orbit, note that the distance traveled is 2 pi r. You have the velocity, so solve for the time.

2 pi r = v t
t = ( 2 pi r ) / v

2007-11-20 16:56:43 · answer #1 · answered by jgoulden 7 · 0 0

Sorry, man but I don't think the question is right and there should be radial acceleration rather than radical and the direction of movement of satellite and that of earth is not stated so even if one tries to get the result it would be incomplete one.

2007-11-21 00:51:30 · answer #2 · answered by razorblade 2 · 0 0

Rate x Time = distance

2007-11-21 00:47:16 · answer #3 · answered by frogshipp 1 · 0 1

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