i hav found x to be 0 or 90... but dont i have more answers like 360 - 90 or something... cant work out where to go from here! have i even got that right? help! its not meant to be hard! :)
2007-11-20 16:42:13 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You talking about this key?
≤
2007-11-20 16:54:42 · answer #1 · answered by Jeƒƒ Lebowski 6 · 0⤊ 3⤋
It would be 0, 90, and 180 (in degrees):
sin 0 = 0
sin 90 = 1
sin 180 = 0
sin^2 x - sin x = 0
sin^2 x = sin x
sin x = 0 or 1
In geometry, 0 = 360 degrees (just like noon could be viewed as zero or 12 on the clock)
Hope this helps! :)
2007-11-20 16:48:47 · answer #2 · answered by disposable_hero_too 6 · 1⤊ 0⤋
sin² x - sin x = 0, 0 ≤ x < 360°.
(sin x)(sin x - 1) = 0
sin x = 0, x = 0 or x = 180°
sin x - 1 = 0
sin x = 1
x = 90°
so x = 0, 90, 180.
2007-11-20 16:54:04 · answer #3 · answered by Philo 7 · 2⤊ 0⤋
sin2x = 2sinxcosx, so 2sinxcosx = sinx whilst 2cosx = a million or cosx = a million/2. (for sinx != 0) or whilst sinx = 0, sin2x additionally = 0, so sinx = 0 or cosx = a million/2. resolve for x: sinx = 0 whilst x = 0, one hundred eighty, 360, ... cosx = a million/2: 60, 3 hundred. x = 0, 60, one hundred eighty, 3 hundred, 360.
2016-11-12 06:54:11 · answer #4 · answered by ? 4 · 0⤊ 0⤋
replace x with sin:
x^2 -x =0
x(x-1) = 0
x = 0 or 1
sin = 0 or 1
x = 90 or 0 or 180
2007-11-20 16:58:19 · answer #5 · answered by sayamiam 6 · 1⤊ 0⤋
less than or equal to is typed like <=
2007-11-20 16:55:28 · answer #6 · answered by Zeta 3 · 1⤊ 1⤋
sin
2007-11-20 16:57:14 · answer #7 · answered by aniesh a 1 · 0⤊ 1⤋