I have the answer to this pre calc problem but I need confirmation?

Question

The question is "Solve the equation 4 sin^2 (x) − 3 = 0."

I got to the point sin(x) = +/- sqr(3)/2
Do I solve for the positive or the negative or both??

Answer 1

both.

Answer 2

Yes both positive and negative. Additionally you should have been given a range to solve on like [0,π] or something as sin is periodic and you will get multiple solutions.

Answer 3

You should be solving for both. You will get 4 solutions in the 0 to 2pi domain, and this repeats in subsequent 2pi intervals.

Answer 4

4sin^2x=3
sin^2x=3/4
sin x= +/- (sqrt 3)/2
x= Sin inverse of +/- (sqrt 3)/2
x= pi/3, 2pi/3 4pi/3, 5pi/3
just add or subtract pi for more answers

so basically to answer ur question solve for both unless u have a specific domain such as -pi

Answer 5

sin^2(x) = 3/4
sin(x) = +/-sqrt(3)/2

x = pi/3, 2 pi/3, 4 pi/3, 5 pi/3

but that is within the domain: {x|-2pi

Answer 6

4*(sin(x))^2=3
(sin(x))^2=3/4
sin(x)=(+/-)[(3/4)^(1/2)]
I'm not sure about factoring out the four but I am pretty sure that you can do that

Answer 7

cos2x = cos^2 x - sin^2 x cos2x = cos^2 x - (a million- cos^2 x) cos2x = cos^2 x - a million + cos^2 x cos2x = 2cos^2 x -a million then, by making use of including a million to the two factors, cos2x+a million = 2cos^2 x then dividing the two factors by making use of two, (cos2x+a million)/2 = cos^2 x

Answer 8

always both, though sometimes in practical problems one of the answers won't make sense to the particular application..