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or maybe you can tell me?

2007-11-20 14:35:02 · 10 answers · asked by Patrick W 2 in Science & Mathematics Mathematics

10 answers

1+1=2. It doesn't equal zero unless it's your adding negative one. -1+1=0.

2007-11-20 14:39:45 · answer #1 · answered by wintergrave 2 · 1 1

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I assume by saying “breakdown” you mean solve this equation so that is what I will do! I’m going to give a brief explanation too, afterall, no point in doing the maths if you haven’t learnt anything!! ;) Solve: x^2 + x – 12 = 0 In order to solve the above equation, we must do something called “factorising”, its basically breaking the equation down into smaller parts, which makes solving it easier. The method for this is as follows: 1)We must find 2 numbers which add to make x and multiply to make 12 2)Put these into separate brackets with the unknown ‘x’ which u want to find 3)Then solve each bracket separately by equating them to zero The 2 numbers which add to make 'x' and multiply to make 12 are -3 and +4 because -3 +4 = 1 and -3 X +4 = 12 We put these into two smaller brackets, like so: (x - 3) X (x + 4) = 0 Which becomes (x – 3)(x + 4) = 0 Note that in algebra the symbol for multiplication disappears. Solving (x – 3) = 0 gives the solution x = 3 Solving (x + 4) = 0 gives the solution x = -4 Hey presto, we’re done!!

2016-04-04 23:10:03 · answer #2 · answered by Anonymous · 0 0

Zero Plus One

2016-12-10 11:56:44 · answer #3 · answered by ? 4 · 0 0

The only explanation is that you're performing integer arithmetic, modulo 2. Modular arithmetic means you always divide the answer by the modulus, then output the remainder. Thus the result of a modular integer operation is always between 0 and m-1, where m is the modulus.

Example 1:
x = 2*6 mod 5
x = 12 mod 5
x = 2

Example 2:
x = 3^5 mod 4
x = 243 mod 13
x = 9

2007-11-20 14:43:36 · answer #4 · answered by lithiumdeuteride 7 · 4 1

coherent integration in radar systems...

they will uses intrapulse modulations to encode the pulse. thus effectively reducing the range resolution. when doing this they perform several repetitions for modulo-2 addition.

if the signal is encoded w/ a barker code, each step will result in alternating 1s & 0s. then all 1 & 0 pair cancel out giving a high spectral power in the center.

pulse encoded w/ 1011

1 s 0100 (1+0 = 0 ; 0+0 =1; 1+1 = 1 ==> all 0s down center = 4)
1 ss 0100 (S's are place holders)
0 ssss1011
1 sssss0100
-----------------
1014101 (symetry indicates barker coding)

2007-11-20 14:55:49 · answer #5 · answered by Anonymous · 3 1

There is no valid explanation for that.

If you want to annoy people you can tell them 1+1=10 but say one zero not ten when you tell them

This is how you write 2 in base two.

2007-11-20 14:43:31 · answer #6 · answered by Nouri K 3 · 1 3

the only way that 1+1=0 is through the base 2 or binary system as opposed to the decimal system whereas 1 and 0 are the only numbers in base 2

0+0=0
0+1=1
1+0=1
1+1=0

2007-11-20 14:41:57 · answer #7 · answered by Dave aka Spider Monkey 7 · 2 4

This is false. There is a special "proof" that people have come up with, but it sneakily utilizes a false rule. It surreptitiously divides by zero. When you divide by zero, any thing's possible. Here's the proof.

We'll start with 2 variables: a and b
Let A=1,
B=1
A=B < A^2=AB < A^2-B^2=AB-B^2 (A-B)(A+B)=B(A-B) A+B=B 1+1=1
2=1 NOw subtract one from both sides
1=0 Now multiply both sides by 2
2=0
1+1=0
****The problem is that we divide by (A-B)... but A-B=1-1=0...uh oh... we divided by zero. And when we divide by zero... anything's possible, but completely wrong!

2007-11-20 14:40:01 · answer #8 · answered by SaintPretz59 4 · 5 1

but it doesn't = 0

2007-11-20 14:38:59 · answer #9 · answered by Anonymous · 1 5

one plus one doesn't equal zero so there is nothing to explain.

2007-11-20 14:39:10 · answer #10 · answered by Anonymous · 1 3

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