2007-11-20 14:26:25 · 5 answers · asked by Dalton 1 in Science & Mathematics ➔ Mathematics
[11]
a^3-3a^2-a+3
=a^2(a-3)-1(a-3)
=(a-3)(a^2-1)
=(a-3){(a)^2-(1)^2}
=(a-3)(a+1)(a-1)
2007-11-20 14:33:33 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
First: 4 terms - group "like" terms.
(a^3 - a) - (3a^2 + 3)
Sec: factor both sets of parenthesis - find the least common factors.
a(a^2 - 1) - 3(a^2 - 1)
(a^2 - 1)(a - 3)
Third: continue to factor...a^2-1...
(a+1)(a-1)(a-3
2007-11-20 22:32:40 · answer #2 · answered by ♪♥Annie♥♪ 6 · 1⤊ 0⤋
3+ a(a^2 -3a -1)
2007-11-20 22:32:33 · answer #3 · answered by hawksup2 3 · 0⤊ 1⤋
a³ - 3a² - a + 3
a²(a - 3) - (a - 3)
(a - 3)(a² - 1)
(a - 3)(a - 1)(a + 1)
2007-11-20 22:31:19 · answer #4 · answered by Marvin 4 · 1⤊ 0⤋
a^3-3a^2-a+3
(a-3)(a^2-1)
(a-3)(a-1)(a+1)
2007-11-20 22:39:32 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋