I think the 4 games were: A vs E, B vs H, C vs G and D vs F.
Here's how I did it (there are probably several ways):
First, each of the predictions gives one member of each of the 4 pairs of teams, so we can tell who did NOT play who:
So, the combinations that can NOT play against each other are:
A vs A, B, F, G
B vs A, B, C, E, F, G
C vs B, C, E, F
D vs D
E vs B, C, E, F, G, H
F vs A, B, E, F, G, H
G vs A, B, E, F, G, H
H vs E, F, G, H
So we are limited to the following combimations that CAN play against each other:
A vs C, D, E, H
B vs D, H
C vs A, D, G, H
D vs A, B, C, E, F, G, H
E vs A, D
F vs C, D
G vs C, D
H vs A, B, C, D
First, by inspection, E had to play A as from the set of 3 (E, F& G) we can easily determine that C & D had to play F & G in some combination. Also, we can now remove C & D from all the other combinations as well. So, now we have:
A vs E
B vs H
C vs A, G, H
D vs B, F, G, H
E vs A
F vs C, D
G vs C, D
H vs B
Now the combination H vs B has appeared, so we can remove H & B from the other lists too:
A vs E
B vs H
C vs G
D vs F, G
E vs A
F vs C, D
G vs C, D
H vs B
Now, C vs G has appeared, so we can get rid of any C & G's on the other lists:
A vs E
B vs H
C vs G
D vs F
E vs A
F vs D
G vs C
H vs B
The logic of solving this is much like that for Sidoku puzzles. It actually took about 10 x as long to explain how to solve, than to solve!
2007-11-20 14:57:55
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answer #1
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answered by Flying Dragon 7
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