A 20.0kg floodlight in a park is supported at the end of a horizontal beam of negligeble mass that is hinged to a pole. A cable at an angle of 30 degrees witht the beam helps to support the light. Find (a) the tension in the cable and (b) the horizontal and veritical forces exerted on the beamm by the pole.
Pls. explain how to do it!
Answers:
a)392N
b)H:339N (to right)
V:0
2007-11-20 13:24:12 · 2 answers · asked by boy101 3 in Science & Mathematics ➔ Physics
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| ..\ T
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Fx Sum of horizontal forces
R-Tcos(30)=0
Fy Sum of vertical forces
mg - Tsin(30)= 0
T= mg/sin(30)=
T=20.0 x 9.81/sin(30)=392 N (rounded to 3 SF)
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R- is the force on the horizontal beam
R=Tcos(30)
R= 392 cos(30)=334 N (The beam is under compression )
Since the tension is to the left the R is apposing it and is directed to the right.
It has no vertical component .
2007-11-20 13:45:14 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
The rigidity on the particle is F = qE from the definition of electric powered field, and the acceleration of the particle is a = F / m from Newton's 2nd regulation, so a = qE / m verify to transform mC to C and nkg to kg, in case you like to get m/s². Hmmm ... working the numbers for myself makes me ask your self whether you meant six hundred ?C?
2016-09-29 22:11:12 · answer #2 · answered by ? 4 · 0⤊ 0⤋