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whats the 5 numbers before the sequence
in other words fill out the blanks...
_ _ _ _ _ 1,1,2,3,5,8,13,21

the sum of 2 sums imediatly after it..

please help!
thankkks :]

2007-11-20 13:03:52 · 6 answers · asked by soccerhamfrog8 1 in Science & Mathematics Mathematics

6 answers

Each number is the sum of the two numbers before, so if you work backwards:

a, b, c, d, e, 1, 1, 2, 3, 5, 8, 13, 21

e + 1 = 1
e = 0

d + e = 1
d + 0 = 1
d = 1

c + d = e
c + 1 = 0
c = -1

b + c = d
b + -1 = 1
b = 2

a + b = c
a + 2 = -1
a = -3

-3, 2, -1, 1, 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, etc.

2007-11-20 13:09:51 · answer #1 · answered by Puzzling 7 · 2 0

there's a general formula for the nth term. If I remember corectly it is: F(n) = 1/ √5 [(1 + √5) / 2]ⁿ - 1 / √5[(1 - √5) / 2]ⁿ

So for example lets say I wanan find the 2nd term of Fibo's Sequence. N is 2.

Now
F(n) = 1/√5 [(1 + √5) / 2]² - 1/√5 [(1 - √5) / 2]²
= 1/ √5 (1/4 + (2√5)/4 + 5/4) - 1/√5 (1/4 - (2√5)/4 + 5/4)
= answer will be 1 (lol hard to type everu=ything I'll leave it down to u. You get the idea... right?)

Anyways, the first number of fibonacci is 1, I don't think there are any negatives. Check with the general formula, see if you get any answers. Hint: for first answer replace n with (-1).

2007-11-20 21:18:09 · answer #2 · answered by Anonymous · 0 0

-3 2 -1 1 0

2007-11-20 21:17:02 · answer #3 · answered by Ron H 2 · 0 1

-3 2 -1 1 0,
keeping the same rule: Each number is
the sum of the previous 2.
Carrying this further we get the rule for the
"negative Fibonacci sequence":
F_ -n = (-1)^(n+1)*F_n.

2007-11-20 21:18:22 · answer #4 · answered by steiner1745 7 · 0 0

well, my guess would be 0,0,0,0,0

2007-11-20 21:10:34 · answer #5 · answered by Harris 6 · 0 3

0,0,0,0,0

2007-11-20 21:09:29 · answer #6 · answered by Anonymous · 0 4

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