A 56.0 kg ballet dancer stands on her toes during a performance with four square inches (26.0 cm2) in contact with the floor. What is the pressure exerted by the floor over the area of contact in the following cases?(a) if the dancer is stationary(b) if the dancer is leaping upwards with an acceleration of 5.00 m/s2
2007-11-20 12:45:18 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Pressure is force divided by area.
(a) If the dancer is stationary, the force exerted on the floor is her weight, mg. The pressure is then mg / area. The answer will be in Newtons / square centimeter unless you want to convert cm^2 into m^2.
(b) If the dancer is accelerating at 5 m/s^2, the net force on her must be F = ma = N - mg. Solve for N, then pressure = N / area.
2007-11-20 13:09:21 · answer #1 · answered by jgoulden 7 · 1⤊ 0⤋