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I need help!!

2007-11-20 11:21:53 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

i dont know what happened but that wasnt the full question! This is

V

A student prepares a solution by dissolving 3.18 g of NaOH in enough water to make 300. mL of solution.
The student then transfers 25.0 mL of this solution into a 100. mL volumetric flask. Water is then added
up to the 100. mL mark.
What is the final molarity of NaOH in the 100. mL flask ?

2007-11-20 11:40:11 · update #1

1 answers

You sure do! Let the solution be called S.

Atomic weights: Na=23 O=16 H=1 NaOH=40

3.18gNaOH/300mLS x 1molNaOH/40gNaOH x 1000mLS/1LS = 0.265 mole NaOH per L solution

Was that what you were looking for?

2007-11-20 11:30:19 · answer #1 · answered by steve_geo1 7 · 0 0

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