How would you solve this equation?
4y+(2x+y)+(79-x)
Please explain too. Thanks!
2007-11-20 11:20:50 · 6 answers · asked by b 5 in Science & Mathematics ➔ Mathematics
It was supposed to equal 180 since it is an isosceles triangle. So the equation is
4y+(2x+y)+(79-x)=180
2007-11-20 11:25:50 · update #1
you cant evaluate it but you can simplify it by doing this
4y+(2x+y)+(79-x)
5y+(3x)+79 this is as simplified as it goes what i did was that 4y plus y ( which is actually 1y ) equals 5y. Theni got 3x by adding x ( which is actually 1x ) plus 2x. then just bring 79 down.... if you cant think of it as variables then try apples and oranges or some other item that you like!!!
HOPE THIS HELPS!!!
GL!!
2007-11-20 11:48:04 · answer #1 · answered by xoxo13em 2 · 0⤊ 0⤋
You need to simplify it.
4y+2x+y+79-x
5y+x+79
Also, It's not an equation. It is an expression
2007-11-20 19:36:16 · answer #2 · answered by Wendy G 2 · 0⤊ 0⤋
You cannot solve this. It has to equal something. But, you can simplify it to 5y+x+79. That is all you can do.
2007-11-20 19:28:18 · answer #3 · answered by Asian336 2 · 0⤊ 0⤋
First of all, it's not an equation.
Second, if you have two variables, you would need at least two equations in order to solve for the two variables.
2007-11-20 19:24:04 · answer #4 · answered by nfactor13 2 · 0⤊ 0⤋
simplify it:
1) 4y+2x+y+79-x
2) 5y+x+79
x and y cannot be solved for with what you have.
2007-11-20 19:23:32 · answer #5 · answered by refdxf 2 · 0⤊ 2⤋
Sorry, but this is not an equation, no equal sign.
.
2007-11-20 19:25:00 · answer #6 · answered by Robert L 7 · 0⤊ 0⤋