The question asks "The X-intercepts of a porabola are 5 and -7. What is the equation of the axis of symmetry? Explain."
I already know the answer is 12 by using simple + and - but is there a way to do it algebraically?
Thanks
2007-11-20 10:31:52 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The answer is not 12. The axis of symmetry is half the sum of the two zeros, i.e. x=(zero_1 + zero_2)/2
x=(5+(-7)/2
=-2/2
=-1
The equation for the axis is symmetry is x=-1.
2007-11-20 10:38:42 · answer #1 · answered by de4th 4 · 0⤊ 0⤋
Well, your answer is actually wrong.
To solve, just find the average of the two intercepts, because the axis of symmetry has to be exactly in the middle (hence the term symmetry).
-7+5=-2
-2/2=-1.
The axis of symmetry is x=-1.
2007-11-20 10:39:49 · answer #2 · answered by Mother Pucker 3 · 0⤊ 0⤋
your axis of symmetry is x= -1... not really sure where you got 12 from
2007-11-20 10:39:56 · answer #3 · answered by ¿ /\/ 馬 ? 7 · 0⤊ 0⤋