Gas Law problem hellp!!?

Question

calculate the volume of SO2(g) produced when 2.00 liters of o2 react with excess sulfer at constant temperature and pressure.

Answer 1

First, the substance is SULFUR, not sulfer.

You need the chem rxn: S + O2 = SO2
Since 1 mole of O2 yields 1 mole of SO2, and ideal gases occupy the same volume per mole, 2 liters of SO2 are produced.

Answer 2

O2(g) + S --> SO2(g)

the comparison of the volume = comparison of coefficient in balanced equation (this is only for gas and aqueous solution)

v(SO2) / v(O2) = 1/1
v(SO2) = v(O2) = 2 L