a)the distance the ball travels before it hits the ground.b) its maximum height?

Question

a player kicks a football from the ground level with a velocity of magnitude 27.0 m/s at an angle of 30.0 degrees above the horizontal.

Answer 1

Let's first determine vertical and horizontal components
Vv= Vsin(30)
Vh=Vcos(30)
We know that
Vv=gt so
t=Vv/g

and finally
A)
Smax= Vht
Smax= Vcos(30) Vv/g
Smax= Vcos(30) Vsin(30)/g
Smax= V^2 cos(30) sin(30)/g
Smax=(27.0)^2 x cos(30) sin(30)/9.81
Smax=32 m

B)
Now since we know the time
h=0.5gt^2 = 0.5 (Vsin(30))^2/g
h=0.5 [27.0 sin (30)]^2/9.81=
h= 9.3m