(x^2 y ^3 z)^3 (x^3 yz^2)?

Question

solve:
(x^2 y ^3 z)^3 (x^3 yz^2)
where x= 0.5, y=2 and z=3

Answer 1

1 phrase: plug-and-chug...

[(.5)^2(2)^3(3) ]^3 [(.5)^3(2)(3)^2]
[.25*8*3]^3[.125*2*9]

= 13.5

Answer 2

5

Answer 3

First, gathering terms, we have:

x^9 y^10 z^5

Substituting values:

(0.5)^9 2^10 3^5

or

(2^10 3^5)/2^9

2 3^5

2 243

486

(Sayamiam's method is OK, but the arithmetic is wrong. Somehow the first term didn't get cubed.)

Answer 4

it relatively is Fermat's final Theorem, that there are actually not any integer ideas to this for exponents extra advantageous than or equivalent to 3. Fermat he mentioned he'd shown it yet there grow to be no area on the paper to place in writing out the evidence. human beings have been specualting approximately it ever because, merely these days it grow to be shown. Gauss, between the perfect mathematicians of all circumstances, became up his nostril at it even nevertheless there grow to be a huge funds prize.

Answer 5

Roger the mole has it right: 486