2007-11-20 08:02:51 · 4 answers · asked by germanmonkey1 1 in Science & Mathematics ➔ Mathematics
the two integers are x and x+1 (i like using x)
3x + 7(x + 1) = 97
3x + 7x + 7 = 97
3x + 7x = 10x
10x + 7 = 97
97 - 7 = 90
10x = 90
then divide 10 into 90
x=9
x+1 = 10
the numbers are 9 and 10
3*9 + 7*10 = 27 + 70 = 97
hoped i helped
2007-11-20 08:28:16 · answer #1 · answered by jesus_died_just_4_us 2 · 1⤊ 1⤋
The two integers are n and n+1
3n + 7(n + 1) = 97
3n + 7n + 7 = 97
10n + 7 = 97 // subtract 7
10n = 90 // divide by 10
n=9
n+1 = 10
The numbers are 9 and 10
3*9 + 7*10 = 27 + 70 = 97
2007-11-20 16:11:09 · answer #2 · answered by Amit Y 5 · 0⤊ 0⤋
y - x = 1
3x + 7y = 97
solve for x and y using substitution:
3x + 7(1+x) = 97
10x + 7 = 97
x = 9
y = 10
2007-11-20 16:08:52 · answer #3 · answered by KEYNARDO 5 · 0⤊ 0⤋
3x + 7(x + 1) = 97
10x = 90
x = 9
Integers are 9 and 10
2007-11-20 16:46:39 · answer #4 · answered by Como 7 · 1⤊ 1⤋