A 57.0 kg person jumps from rest off a 11.0 m high tower straight down into the water. Neglect air resistance during the descent. She comes to rest 3.00 m under the surface of the water. Determine the average force that the water exerts on the diver. This force is nonconservative.
2007-11-20 07:52:47 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
ive tried 2048.2, which is (mgh)/3, but its not correct
2007-11-20 08:30:47 · update #1
what would i use for h and d?
2007-11-20 08:58:35 · update #2
Assuming down is negative: 2048.2 N.
2007-11-20 07:58:05 · answer #1 · answered by Sheen J 1 · 1⤊ 0⤋
Use this formula:
Change in kinetic energy = (average force)×(distance)
In symbols:
ΔKE = (F_avg)(d)
When she's at the top of the tower, she has a certain amount of potential energy (PE), and no KE. That energy is converted entirely into KE by the time she hits the water. So:
ΔPE = ΔKE
So:
ΔPE = (F_avg)(d)
ΔPE equals mgh. They give you "m", "h" and "d". Solve for F_avg.
2007-11-20 08:31:27 · answer #2 · answered by RickB 7 · 0⤊ 0⤋
according to probability you will desire to evaluate that the entire rigidity on the diver will additionally think with regard to the downward rigidity of gravity. If the rigidity upwards on the diver replaced into 980N then the entire rigidity on the diver would be 0N (as gravity would be 980N down). try including 980N on your answer (or 981N counting on how precise you may desire to be approximately that fee.)
2016-10-02 03:43:17 · answer #3 · answered by ? 3 · 0⤊ 0⤋