2007-11-20 06:53:27 · 6 answers · asked by PDF 2 in Science & Mathematics ➔ Mathematics
Zero
3*(infinity)-1 = infinity
1/infinity = so close to zero
2007-11-20 06:57:11 · answer #1 · answered by Anonymous · 2⤊ 0⤋
The easy way to solve this is to substitute some large numbers for X and use your calculator. If X is 100, your expression is 3.34 x 10^(-3). If X is 10,000, your expression is 3.33 x 10^(-5). Since the 3X -1 gets larger as X gets larger, 1/(3X-1) will keep getting smaller as X gets larger. 1 divided by a large number cannot be negative, and it can never quite reach zero, but it will get very close to zero as X gets large.
2007-11-20 07:02:19 · answer #2 · answered by Anonymous · 0⤊ 0⤋
when taking x to infinity you ignore all lower powers of x or constants for example
(x^2 - 2x)
in this case 2x is irrelevant as x^2 is alot larger so this tends to +infinity.
in your case 1/3x-1 the one doesnt matter here as 3x as x goes to infinity will be so much bigger
so it will just be 1/3x which is 1/3(infinity) which is 0
2007-11-20 07:03:36 · answer #3 · answered by Anonymous · 0⤊ 0⤋
One way to do limits is plugging directly in. Of course you can't plug in infinity so you plug in 999999 (Just a very large number to represent infinity). When you plug it into your calculator, you get some number in scientific notation with a large negative exponent which means it a very small number. so it basically approaches 0
2007-11-20 06:58:40 · answer #4 · answered by Alexis P 2 · 0⤊ 0⤋
yeah.. they are right!
try plugging in a very large number for x. so, then it's just logic; one divided by a very large number would be close to zero, so the limit is zero.
2007-11-20 07:05:36 · answer #5 · answered by xdx 2 · 0⤊ 0⤋
zero
2007-11-20 06:56:57 · answer #6 · answered by norman 7 · 0⤊ 0⤋