Changing subject in a formula:?

Question

Make c the subject:
a) V = (x^2*c)/3

b) V = (c^2*h)/3

c) c - 4e^2= 5 - 2c

Answer 1

a) 3V/x²
b) √(3V/h)
c) (5+4e²)/3

Answer 2

Question a)
3 V = c x ²
c = 3 V x ²

Question b)
3V = h c ²
c ² = 3V / h
c = √ (3V / h)

Questiion c)
3 c = 5 + 4 e ²
c = (5 + 4 e ²) / 3

Answer 3

V = (x^2*c)/3
3V = x^2*c
c = 3V/x^2


V = (c^2*h)/3
3V = c^2*h
3V/h = c^2
c = sqrt (3V/h)


c - 4e^2= 5 - 2c
3c - 4e^2 = 5
3c = 4e^2 + 5
c = (4e^2 + 5)/3

Answer 4

a) V = (x^2*c)/3
3v=x^2 x c --> times by 3 to both sides
c=3v / x^2 --> divide vy x^2 to both sides

b) V = (c^2*h)/3
3v=c^2 x h --> times by 3 to both sides
3v / h=c^2 -->divide by h to both sides
c= + √(3V/h) -->square root each side
or
c= - √(3V/h) -->square root each side

c) c - 4e^2= 5 - 2c
c=(-2c)+5+4e^2 --> add 4e^2 to both sides
3c=5+4e^2 -->add 2c to both sides
c=(5+4e^2) / 3 -->divide by 3 to each side

Answer 5

a)
V = (x² * c)/3
3V = x² * c
C = 3V / x²

b)
V = (c² * h)/3
3V = c² * h
3V /h = c²
C = √3V /h

c)
c - 4e² = 5 - 2c
3C = 5 + 4e²
3 = (5 + 4e² ) / 3

Answer 6

a) c=3V/x^2

b) c=squareroot(3V/h)

c) c=(4e^2+5)/3