A person doing a chin-up weighs 710 N, disregarding the weight of the arms. During the first 27.0 cm of the lift, each arm exerts an upward force of 365 N on the torso. If the upward movement starts from rest, what is the person's speed at this point?
2007-11-20 03:05:23 · 1 answers · asked by andyjumpman23 3 in Science & Mathematics ➔ Physics
2 a ( y - yo) = v ^2 - vo ^2
a is acceleration
yo is initial height; call it zero
y is final height, 27 cm or .27 m
v is final velocity (what you're looking for)
vo is initial velocity, zero
The problem says that the person has a weight of 710 N, so you can find the mass of the person using 710 N = m g where g is the acceleration of gravity, 9.8 m/s^2. Now you can find the acceleration using 365 N = m a, then use that acceleration in the equation above to find v.
2007-11-20 03:35:44 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋