2/5=z-12/z-9
2007-11-20 01:39:40 · 14 answers · asked by ann m 1 in Science & Mathematics ➔ Mathematics
This looks like a quadratic equation:
>>Multiply both sides by 5
>>2=5z - 60/z - 45
>>Multiply both sides by z
>>2z = 5z^2 - 60 - 45z
>>Make one side of the equation equal to zero
>>5z^2 - 47z - 60 = 0 (this is the quadratic equation to solve)
The quadratic equation formula is:
x = [-b ± (b^2 – 4ac)^-2]/2a
where a = 5, b = -47, c =-60
>>substitute values back into formula but notice that you'll have to do this twice ( + and -) therefore you will get two possible answers of x
>>x = [-b + (b^2 – 4ac)^-2]/2a
>>x = 10.539
>>x = [-b - (b^2 – 4ac)^-2]/2a
>>x = -1.139
2007-11-20 02:13:19 · answer #1 · answered by audereestfacere100 1 · 0⤊ 0⤋
Z=3
2007-11-20 01:41:39 · answer #2 · answered by Googler 4 · 0⤊ 1⤋
3
2007-11-20 01:43:28 · answer #3 · answered by Anonymous · 0⤊ 1⤋
z = 3 because:
12/3 = 9
2007-11-20 01:42:07 · answer #4 · answered by Cat 7 · 0⤊ 1⤋
2/5 = (z-12)/(z-9)
2(z-9)=5(z-12) (cross-multiplication)
2z-18=5z-60
2z-5z=-60 + 18
-3z=-42
z=(-42)/(-3)
z=14
2007-11-20 01:52:17 · answer #5 · answered by Kenneth Koh 5 · 0⤊ 0⤋
z-12 = 2z-18 / 5
5z - 60 = 2z - 18
5z = 2z - 18 + 60
5z - 2z = 60-18
3z = 42
z = 42 / 3 = 14
2007-11-20 01:49:20 · answer #6 · answered by alatoruk 5 · 0⤊ 0⤋
multiply (z-9)(5) on both sides to eliminate all denominator
2(z-9)=5(z-12)
2z-18=5z-60
3z=42
z=14
2007-11-20 01:43:17 · answer #7 · answered by someone else 7 · 0⤊ 1⤋
2/5= z-12/z-9
Cross multiplying,
2z-18=5z-60
3z=42
z=14
2007-11-20 01:57:53 · answer #8 · answered by Arunachalesa 3 · 0⤊ 0⤋
z=39
2007-11-20 01:43:23 · answer #9 · answered by Faith H 1 · 0⤊ 1⤋
the Z equals 3 mate
2007-11-20 01:43:17 · answer #10 · answered by Anonymous · 0⤊ 1⤋