a rope is used to pull a 10 kg block across the floor ...?

Question

a rope is used to pull a 10 kg block across the floor with an acceleration of 3 m/s2. if frictional force acting on the block is 50 N. what is the tension on the rope?

thanks

Answer 1

Given:
10 kg = m, mass of the block being pulled
3 m/s^2 = a, acceleration of the block
50 N = Ff, frictional force acting on the block

Find:
Ft = tension on the rope

Solution:
Fnet = ma
Ft - Ff = ma
Ft = ma + Ff
Ft = (10kg)(3 m/s^2) + 50 N
Ft = 30 N + 50N
Ft = 80 N ANS.

teddy boy

Answer 2

Tension T on the rope is the sum of force accelerating the block F and force of friction f:
T=F+f
T=ma+50=10 x 3 + 50N=80

Answer 3

Newton's second law states that the resulting force F is equal to mass times acceleration, so F in this case is 10kg*3 m/s^2 or 30 N. This resulting force is composed of two forces: the frictional force and the tension, which are opposite in direction. (Assuming that the pulling is being done parallel to the floor - otherwise we don't have enough information to solve the problem). As the friction is 50N, the tension on the rope must be 80N.

Answer 4

This is a dynamics problem...

The sum of the horizontal forces = m*a

The horizontal forces are tension and friction with friction acting opposite of tension and the direction of acceleration. Therefore,

m*a = T - friction

T = m*a + friction

T = 10*3 + 50 = 80 N