If "x" men can do a job in "h" days, how long would "y" men take to do the same job.
A)x/h
b)xh/y
c)hy/x
d)xy/h
Please show step by step if possible. Thanks
2007-11-19 22:44:02 · 6 answers · asked by Sufian 2 in Science & Mathematics ➔ Mathematics
xh = yd
Solve for "d"
Multiply sides by 1/y to solve for d
The answer is actually xh/y
Answer "b" is correct
2007-11-19 23:04:58 · answer #1 · answered by Your Uncle Dodge! 7 · 1⤊ 0⤋
x men:h days=y men :k days
inversely proportion
therefore xh=yk
k=xh/y
b
2007-11-19 22:56:25 · answer #2 · answered by someone else 7 · 1⤊ 1⤋
Since x men can do a job in h days it follows that 1 man can do the job in h*x days (when he works alone).
Therefore one man does 1/(h*x) of the job in one day.
Then y men do y/(h*x) of the job in one day.
From here we conclude that y men have to work (h*x)/y days in order to do the job. Answer b.
2007-11-19 22:58:41 · answer #3 · answered by evtrina 1 · 1⤊ 2⤋
Your best option is to ask Charles Xavier
2007-11-19 22:53:30 · answer #4 · answered by musclebobbuffpants01 4 · 0⤊ 3⤋
i dont think i can expliain it but the answer id d
2007-11-19 22:57:15 · answer #5 · answered by Shahbaz 2 · 1⤊ 3⤋
the answer is A (x/h)
y= x/h
because we want x and y to be equal so therefore its x/h
2007-11-19 22:55:54 · answer #6 · answered by ryukansentsumuji01 2 · 0⤊ 4⤋