3 x 3 = ?, erm?

Question

how can i arrange the digits from 10 to 18 in a 3x3 table like so that every row, column and diagonal totals the same amount.

any ideas how that is done, or how i can do it?

Answer 1

the basic idea is
get the mean of these numbers the sum of these numbers & dvivde it by 9 (their number)
10--->18 = 9(18+10)/2/9 = 28/2 =14
put this number in the center and make the sum of any row or column equals to 14 *3

e.g.
13 ?? 11
?? 14 ??
17 ?? 15
then complete the missing by subtacting from 3*14 (42)
42 -11-13 = 18
42-11-15= 16
42-13-17=12
42-17-15=10
so it is
13 18 11
12 14 16
17 10 15

Answer 2

Basically this is a magic square. If you take a normal magic square, you can just add 9 to every number to get what you want.

For example
8 1 6
3 5 7
4 9 2

Becomes:
17 10 15
12 14 16
13 18 11

Totals = 42

Various rotations and reflections are possible too (total of 8).

Answer 3

15 16 11
10 14 18
17 12 13

Basically, you take any magic 3x3 square using the digits 1 through 9, and add 9 to every entry.

Answer 4

18,10,14
13,17,12
11,15,16