2007-11-19 18:52:32 · 4 answers · asked by starrynight 4 in Science & Mathematics ➔ Mathematics
Hmm... you like asking this question. :-)
First factor the expressions:
x² - 9 = (x - 3)(x + 3)
x² + 5x + 6 = (x + 2)(x + 3)
Next look at the two factorizations. You need an (x - 3) and (x + 3) for the first expression.
For the second one, you already have an (x + 3) so you just need to add an (x + 2). Multiply them all together to get the final answer.
The LCM would be: (x - 3)(x + 3)(x + 2)
2007-11-19 19:01:40 · answer #1 · answered by Puzzling 7 · 1⤊ 0⤋
I understand the problem as the LCM of :
(x^2 - 9) and (x^2+5x+6)
(x^2 - 9) = x^2 - 3^2 = (x+3)*(x-3)
(x^2+5x+6) = (x+2)*(x+3)
â´ the LCM is = (x-3)*(x+3)*(x+2)
2007-11-20 03:07:40 · answer #2 · answered by Venkat R 6 · 0⤊ 0⤋
((x^2-9)=(x-3)(x+3)
x^2+5x+6=(x+2)(x+3)
Lcm of these 2 are the product of theirs factors but you do not multiply their common factor twice
therefore lcm=(x-3)(x+3)(x+2)
2007-11-20 02:55:03 · answer #3 · answered by someone else 7 · 0⤊ 0⤋
x^2-9 = (x+3)(x-3)
x^2+5x+6 = (x+3)(x+2)
now after factorisation take higest powe of each of terms toget
(x+3)(x-3)(x+2)
2007-11-20 02:58:26 · answer #4 · answered by Mein Hoon Na 7 · 0⤊ 0⤋