2007-11-19 17:37:30 · 6 answers · asked by Frank Le 1 in Science & Mathematics ➔ Chemistry
Each molecule contains two atoms of N and 5 atoms of O, for a total of 7 atoms per molecule. Then 18 molecules have 7*18 = 126 atoms
2007-11-19 17:41:23 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
Every molecule of N2O5 includes 2 atoms of Nitrogen and 5 atoms of Oxygen.
So every molecule of N2O5 has 7 atoms.
So 18 molecules of N2O5 have 7*18=126 atoms.
2007-11-19 18:02:37 · answer #2 · answered by Ehsan 2 · 0⤊ 0⤋
Each molecule of N2O5 contains 7 atoms (2 nitrogen atoms and 5 oxygen atoms).
If you have 18 molecules, simply multiply.
Total atoms = 18 * 7 = 126
2007-11-19 17:43:49 · answer #3 · answered by Katy D 4 · 0⤊ 0⤋
7 atoms in 1 molecule of N2O5
7*18=126 atoms in 18 molecules of N2O5
2007-11-19 17:42:42 · answer #4 · answered by brindha 2 · 0⤊ 0⤋
1 molecule of N2O5 contains 7 atoms, 2 Nitrogen and 5 Oxygen.
Therefore, 18 molecules contain 18x7 = 126 atoms.
2007-11-19 18:00:46 · answer #5 · answered by jervois.east 2 · 0⤊ 0⤋
in one molecule of N2O5 there are 7 atoms. in 18 there are 7 * 18 = 126 atoms
2007-11-19 17:42:57 · answer #6 · answered by Melissa (theORANGEone) 1 · 0⤊ 0⤋