A party store ordered 50 cases of balloons. The number of cases in stock t months after the order arrives is given by the equation
n(t)= 50e^-0.3t
How many cases are in stock when the order arrives?
How many cases are in stock 6 months after the order arrives?
2007-11-19 16:29:03 · 2 answers · asked by Nidhi M 1 in Science & Mathematics ➔ Mathematics
When the order arrives, t = 0 (zero months after it arrives).
Thus n(t) = 50 e^0 = 50 (since e^0 = 1)
when t = 6
n(t) = 50 e^(-0.3*6)
= 8.265
but you can't really have 0.265 cases of balloons so assume a whole one got shipped. Thus you have 8 cases left after 6 months.
2007-11-19 16:38:13 · answer #1 · answered by Fan Of The semicolon 2 · 0⤊ 0⤋
n(0) = 50e^(-0.3(0)) = 50•1 = 50
n(6) = 50e^(-0.3(6)) = 50e^(-1.8) = 50(0.16530) = 8.2649, or about 8 cases.
2007-11-20 00:35:05 · answer #2 · answered by Philo 7 · 0⤊ 0⤋