rings do not have corners, but if they are standing on opposite sides directly across from each other, it would be 20ft
2007-11-19 16:30:38
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answer #1
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answered by Anonymous
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You need the Pythagorean thereom to solve this. a^2 + b^2 = c^2. You're trying to find the hypotenuse, or c. Both a and b = 20 in this case, so you're solving for the square root of 20^2 + 20^2. I'll let you do the math part.
2007-11-20 00:26:46
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answer #2
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answered by stephieSD 7
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A ring is made of an infinite number of straight segments so it would be kind of hard to do 20' x infinite. What is the length of either the radius (easiest) or diameter? That's what you need to find out first. If the radius is 10' then they are 20' apart.
2007-11-20 00:28:08
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answer #3
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answered by Thomas L 3
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If the ring has a circumference of 20 feet, the diameter is 6.366197723675814 feet. The two people are 6.4 feet apart.
2007-11-20 00:25:35
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answer #4
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answered by Anonymous
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If you mean a boxing ring they would be 20*sqrt(2) = 28.28ft apart. Assuming they are right on the edge.
2007-11-20 00:28:05
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answer #5
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answered by perplexed* 3
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40 feet
2007-11-20 00:33:55
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answer #6
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answered by sivasai 1
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well "corners" would be ooposite sides i suppose, which means they will always be 20 ft apart.
2007-11-20 00:27:59
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answer #7
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answered by Anonymous
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"Ring" usually means circle, which doesn't have sides. So just how many sides (corners) does your polygonal "ring" have?
2007-11-20 00:27:10
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answer #8
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answered by Philo 7
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hmm a ring doesnt have corners!
2007-11-20 00:25:16
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answer #9
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answered by ? 3
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There are no corners.
2007-11-20 00:24:55
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answer #10
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answered by Anonymous
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