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10 answers

rings do not have corners, but if they are standing on opposite sides directly across from each other, it would be 20ft

2007-11-19 16:30:38 · answer #1 · answered by Anonymous · 0 1

You need the Pythagorean thereom to solve this. a^2 + b^2 = c^2. You're trying to find the hypotenuse, or c. Both a and b = 20 in this case, so you're solving for the square root of 20^2 + 20^2. I'll let you do the math part.

2007-11-20 00:26:46 · answer #2 · answered by stephieSD 7 · 1 0

A ring is made of an infinite number of straight segments so it would be kind of hard to do 20' x infinite. What is the length of either the radius (easiest) or diameter? That's what you need to find out first. If the radius is 10' then they are 20' apart.

2007-11-20 00:28:08 · answer #3 · answered by Thomas L 3 · 0 1

If the ring has a circumference of 20 feet, the diameter is 6.366197723675814 feet. The two people are 6.4 feet apart.

2007-11-20 00:25:35 · answer #4 · answered by Anonymous · 0 1

If you mean a boxing ring they would be 20*sqrt(2) = 28.28ft apart. Assuming they are right on the edge.

2007-11-20 00:28:05 · answer #5 · answered by perplexed* 3 · 1 0

40 feet

2007-11-20 00:33:55 · answer #6 · answered by sivasai 1 · 0 0

well "corners" would be ooposite sides i suppose, which means they will always be 20 ft apart.

2007-11-20 00:27:59 · answer #7 · answered by Anonymous · 0 1

"Ring" usually means circle, which doesn't have sides. So just how many sides (corners) does your polygonal "ring" have?

2007-11-20 00:27:10 · answer #8 · answered by Philo 7 · 0 1

hmm a ring doesnt have corners!

2007-11-20 00:25:16 · answer #9 · answered by ? 3 · 0 1

There are no corners.

2007-11-20 00:24:55 · answer #10 · answered by Anonymous · 0 2

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