If you have 240mL of water at 10.5 degrees Celcius and a 45 gram ice cube was added, how much ice remains?

Question

240mL of water = 240 grams of water
ice=0 degree celcius
(i got 31.6grams as my answer)

Answer 1

If you have excess ice, the mixture will end up at 0 C.

Amount ice melted x latent heat of fusion of ice = heat gained by ice = heat lost by water = 240g x 4.184 J g-1 K-1 x 10.5 K

Ice remaining = original amount - amount melted

Provided your units are consistent (if you use the molar heat of fusion of ice, you need to multiply by 18.0 to get g ice melted) this will give you the right answer.

Answer 2

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