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Using an online program, I just crossed a Drosophilia:

Wild type female for antennae and aristopedia shaped antennae for the male. With no information on which allele is recessive or dominant, any ideas on which is?

I am having some serious problems with this.

Thanks!

2007-11-19 15:42:25 · 5 answers · asked by surya0902 2 in Science & Mathematics Biology

5 answers

I agree with Naz.

This is how the cross would look:

Female is Xa Xa.
Male is XA Y.

a = wild type
A = aristopedia

P1 Xa Xa x XA Y
Gametes from female: Xa and Xa. Put these on the left side of the Punnett square.
Gametes from male: XA and Y. Put these on the top of the Punnett square.

Answer boxes in Punnett square ...
First row: XaXA and Xa Y.
Second row: same as the first row.

Phenotypes of F1:
XaXA = females with aristopedia antennae.
XaY = males with wild-type antennae.

There's your 1:1 ratio, giving you 1/2 of each type.

2007-11-19 17:01:48 · answer #1 · answered by ecolink 7 · 0 0

the definition of wild type is the most common genetic feature of the species in its natural environment. So- without looking at the actual question im assuming that the wild type is dominant (most of the time they are). This would mean that since you got half and half you could have gotten any number of combinations. (this would be so much easier to explain if i could draw a picture) - fyi the first set of alleles of the cross is the female.
RRxRr = 2 RR, 2 Rr
Rr x rr = 2 Rr , 2 rr

Thats kind of as much as i can give you with the info in your question- if you want to let me know some more info if thats possible i might be able to help out more
* dont forget to think about it possibly being a sex linked trait as well.
Good luck

2007-11-20 00:13:46 · answer #2 · answered by ges6431 3 · 1 1

The gene for aristopedia occurs in the X chromosomes and it is dominant, this explains your result. All the males are normal because they received the X chromosome from their mother. All females are aristopedia because the aristopedia gene on the X chromosome they received from their father is dominant over wild type antennae.

2007-11-20 00:27:16 · answer #3 · answered by naz 5 · 1 0

The way you worded this question, I can't understand what you're asking.

2007-11-19 23:50:36 · answer #4 · answered by Anonymous · 0 1

if u get 1/2 of each it means that they r both Heterozzygous....
there is one recessive and one domminant....(Mm)

2007-11-20 00:15:49 · answer #5 · answered by ♥ mayra 3 · 0 2

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