Generally, how much space would a rough carpenter leave in between the rough 2 x 4 door opening and the prehung door? I would imagine only an inch or so, but I'm not sure. Thanks.
2007-11-19 14:56:29 · 9 answers · asked by wonderer 1 in Home & Garden ➔ Do It Yourself (DIY)
RO for a prehung 2668 (2'6" x 6'8")door is 32" x 82"
2007-11-19 14:59:54 · answer #1 · answered by maplewoodjoe 4 · 3⤊ 0⤋
The opening should be 32 1/2" wide and 82 1/2" high. That leaves 1" of play on the sides to adjust the door unit to plumb and enough head space for adjustment and for the door casing to cover the opening with room to nail to header.
2007-11-19 15:46:32 · answer #2 · answered by Turnhog 5 · 0⤊ 0⤋
Add Two inches on the width so it would be 32" wide and add 2-1/2 " in height. a total hieght of 82-1/2"
R.O. (rough opening) for 2'-6" x 6'-8" door == 2'8" x 6'10-1/2"
this allows for shims to plumb and level the door in the opening and gives clearances for floorings and trim covers all gaps later.
2007-11-19 15:10:28 · answer #3 · answered by Chris 2 · 5⤊ 0⤋
the one thing no one mentions is assuming the rough in is plumb straight up and down ,,,,check that 1st in to days world of inexperienced carpenters check that before thinking it should be 82-82 1/2x32-32 1/2
2007-11-19 22:47:34 · answer #4 · answered by txtx 4 · 0⤊ 0⤋
Split the 10 between maple and Chris, or at least say thank you to both. Smiles
Steven Wolf
2007-11-19 16:07:54 · answer #5 · answered by DIY Doc 7 · 0⤊ 0⤋
yes , you are correct. normally an inch to adjust square and plumb. most rough openings are close but not perfect and the extra room allows for shimming.
2007-11-19 15:54:03 · answer #6 · answered by cookie 4 · 0⤊ 1⤋
about 2 inches maybe more do to frame size
2007-11-19 15:40:20 · answer #7 · answered by cowboy_up1963 1 · 0⤊ 0⤋
Depends on if i know you well or not. More than likely i would ring the door bell, its the polite thing to do..
2016-05-24 06:54:07 · answer #8 · answered by ? 3 · 0⤊ 0⤋
a 2 x 4 is not really 2'' x 4 '' its smaller
2007-11-19 15:00:06 · answer #9 · answered by edgar m 1 · 0⤊ 5⤋