I got 2, but the book says 0. Can anyone help?
2007-11-19 14:31:30 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The derivative of x^2 is 2x, if x = 0 then, 2 times 0 = 0.
2007-11-19 14:35:28 · answer #1 · answered by Naruto #1 4 · 1⤊ 0⤋
The derivative of x^2 is 2x.
2(0)=0
2007-11-19 14:36:06 · answer #2 · answered by Small Victories 4 · 1⤊ 0⤋
Note that the derivative of x^n = nx^(n-1).
Therefore, the derivative of x^2 is 2x.
Now plug in 0 for x. 2 times 0 is 0, so this is why your derivative is 0.
2007-11-19 14:47:34 · answer #3 · answered by Nitro 5 · 1⤊ 0⤋
The derivative would be 2x (power rule - bring the exponent to the front and drop the exponent down 1)
Plug x=0 into the 2x, so 2(0)=0
2007-11-19 14:36:15 · answer #4 · answered by shaan 4 · 1⤊ 0⤋
Derivative of x² = 2x.
2x evaluated at 0 is 0.
2007-11-19 14:41:20 · answer #5 · answered by steiner1745 7 · 1⤊ 0⤋
y=x^2
dy/dx=2x
Substitute 0 for x
dy/dx=2(0)
dy/dx=0
2007-11-19 14:35:20 · answer #6 · answered by topher098321 2 · 2⤊ 0⤋