Two straight parallel wires carry current equal in mag but opposite in direction. What's the net magnetic field due to these two wires at point a, midway between the wires.
a. directly to the right
b. directly to the left
c. directly upward.
Diagram:
http://session.masteringphysics.com/problemAsset/1019994/2/20-6.jpg
2007-11-19 14:03:20 · 2 answers · asked by ~Brigit~ 2 in Science & Mathematics ➔ Physics
The answer is a.
Use the right hand rule and will see that the magnetic field in each case is rotating counter clockwise.
2007-11-19 14:14:12 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
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(a)directly to the right
The magnitude of magnetic field B [ =(mu not)I /2(pi) s] due to each will be same but directions will be inclined and resultant will be=Bo= [2(mu not)I sin theta /2(pi) s ], where sin theta=L/2s and I is current
the cos components get cancelled
resultant magnetic field=Bo=(mu not)I L/2(pi) s^2
the direction is away from wires to the right
L is separation between wires and s is distance of point 'a' from one wire
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2007-11-19 23:27:24 · answer #2 · answered by ukmudgal 6 · 0⤊ 0⤋