Explain the effect on voltage, current, and resistance when a second lightbulb is added to a circuit.?

Question

Explain by using infomation regarding the definition of a load and the movement of electrons

the bulbs are added in series. Explain by using infomation regarding the definition of a load and the movement of electrons

Answer 1

OK, 2nd bulb is in series. Assume the same type bulb. The load doubles. Electrons have to fight their way through both bulbs to make it through the entire load.

I don't know if the voltage is controlled to a constant or if the current is. Or perhaps neither is constant. But I'm going to guess the voltage remains constant.
V = I*R
The load, R, doubles so the current, I, is cut in half.

Answer 2

Not knowing whether the bulb is added in series with another bulb or in parallel it is difficult. If the bulb is added in parallel, more power would be consumed, more current delivered which could lower the voltage across the bulbs actually decreasing their resistance some. The hotter a filament gets, the higher its resistance. If a bulb is added in series with another bulb, the voltage on both would decrease, lowering their resistance some but increasing the series resistance thus decreasing the power consumed and the amps delivered to the circuit. Not knowing the output resistance of the voltage source makes it hard to predict how much the voltage would rise given a reduction in current.

Answer 3

Depends on whether the bulb is added in series or parallel to the first one..